Note: Any fact not provided here will NOT be provided during the examination, and it is the student's responsibility to memorize it (if necessary).
R = 8.314 47 J K -1 mol -1 = 8.314 47 × 10 -2 L bar K -1 mol -1 = 8.205 74 × 10 -2 L atm K -1 mol -1 = 6.236 37 × 10 1 L Torr K -1 mol -1.
k = 1.380 65 × 10 -23 J K -1.
g = 9.81 m s -2.
1 J = 1 kg m2 s -2.
1 W = 1 J s-1.
1 N = 1 kg m s -2.
1 Pa = 1 N m -2 = 1 kg m -1 s -2 = 1 J m -3.
1 atm = 101.325 kPa.
1 bar = 1.0 × 105 Pa.
1 Torr = 101325/760 Pa (exactly)
w = -nRT ln(Vf / Vi).
w = -CV ΔT.
ViTi c = VfTf c, c = CV, m/R.
pV&gamma = constant, &gamma = Cp, m / CV, m. For monoatomic perfect gas, CV, m = 3R/2. For non-linear polyatomic perfect gas, CV, m = 3R.
Cp, m = 20.786 J K -1 mol -1 for He, Ne, Ar, Xe.
G(pf) = G(pi) + nRT ln(pf/pi).
G(pf) = G(pi) + Vm(pf - pi).
Gm = Gm* + RT ln(f/p*).
f = φ p.
(p - p*)/p* ≈ VM ΔP/RT
dp/dT = ΔtrsS / ΔtrsV.
p = p* + (ΔfusH/ΔfusV)ln(T/T*).
p ≈ p* + (ΔfusH/ΔfusV)(T - T*).
d ln p/dT = Δ vapH/RT2.
p = p* e -χ, &chi =Δvap(T -1 - T* -1) /R.
dw = γ dσ.
pin = pout + 2γ/r.
h = 2γ/ρgr.
dV = V
V= nAVA + nBVB, binary mixture.
G = nAμA + nBμB, binary mixture.
nAdμA + nBdμB = 0; Σ nJdμJ = 0.
Δmix G = nRT(xA ln xA + xB ln xB), for perfect gases
Δmix S = -nR(xA ln xA + xB ln xB), for perfect gases
pA = xA pA*.
pB = xB KB.
μA*(g) = μA*(l) + RT xA.
ΔT = KxB, K = RT*2/ΔvapH.
ΔT = Kbb, Kb is ebullioscopic constant.
μA*(s) = μA*(l) + RT xA.
ΔT = K'xB, K' = RT*2/ΔfusH.
ΔT = Kfb, Kf is cryoscopic constant.
F = C - P +2
p = pA + pB = p*B + (p*A - p*B) xA, in terms of xA.
p = pA*pB / [p*A + (p*B - p*A) yA], in terms of yA.
yA = xAp*A / [p*B + (p*A - p*B) xA].
nα lα = nβ lβ.
k = AeE/RT.
Lindemann-Hinshelwood mechanism: d[P]/dt = kakb[A]2 / (kb + ka'[A]).
Units are an essential part of the answer, unless a unitless quantity is requested in the problem. Answers without units are WRONG, and will receive zero credit.
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